TUGAS TKJ
19-11-2014
TENTANG NETWORK
IP, BROADCAST IP & RANGE IP
KELAS: XII TKJ 2
1. Sebuah
komputer memiliki IP 192.168.11.15 & subnetmask 255.255.255.240
a). tentukan
network IP!
b). tentukan
broadcast IP!
c). tentukan
range IP!
a). 192.168.11.17 = 10101100.10101000.00001011.00001111
255.255.255.240 = 11111111.11111111.11111111.11110000+
= 10101100.10101000.00001011.00000000
= 192.168.11.0
b). 10101100.10101000.00001011.00001111
00000000.00000000.00000000.00001111+
<-(reverse subnetmask)
= 10101100.10101000.00001011.00001111
= 192.168.11.15
c). network IP + 1 = 192.168.11.1
broadcast
IP – 1 = 192.168.11.14
range IP =
192.168.11.1 ~ 192.168.11.14

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